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18x^2-29x-70=0
a = 18; b = -29; c = -70;
Δ = b2-4ac
Δ = -292-4·18·(-70)
Δ = 5881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{5881}}{2*18}=\frac{29-\sqrt{5881}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{5881}}{2*18}=\frac{29+\sqrt{5881}}{36} $
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